(X^2+9x-17)=0

Solution for (X^2+9x-17)=0 equation:

(X^2+9X-17)=0

We get rid of parentheses

X^2+9X-17=0

a = 1; b = 9; c = -17;
Δ = b2-4ac
Δ = 92-4·1·(-17)
Δ = 149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{149}}{2*1}=\frac{-9-\sqrt{149}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{149}}{2*1}=\frac{-9+\sqrt{149}}{2}
$